482. License Key Formatting (Easy)
https://leetcode.com/problems/license-key-formatting/
You are given a license key represented as a string S which consists only alphanumeric character and dashes. The string is separated into N+1 groups by N dashes.
Given a number K, we would want to reformat the strings such that each group contains exactly K characters, except for the first group which could be shorter than K, but still must contain at least one character. Furthermore, there must be a dash inserted between two groups and all lowercase letters should be converted to uppercase.
Given a non-empty string S and a number K, format the string according to the rules described above.
Example 1:
Input: S = "5F3Z-2e-9-w", K = 4 Output: "5F3Z-2E9W" Explanation: The string S has been split into two parts, each part has 4 characters. Note that the two extra dashes are not needed and can be removed.
Example 2:
Input: S = "2-5g-3-J", K = 2 Output: "2-5G-3J" Explanation: The string S has been split into three parts, each part has 2 characters except the first part as it could be shorter as mentioned above.
Note:
- The length of string S will not exceed 12,000, and K is a positive integer.
- String S consists only of alphanumerical characters (a-z and/or A-Z and/or 0-9) and dashes(-).
- String S is non-empty.
Solutions
class Solution {
// The given string S could only contain dashes which is a corner case.
public String licenseKeyFormatting(String S, int K) {
S = S.replace("-", "");
S = S.toUpperCase();
int len = S.length();
if (len <= K) {
return S;
}
String ans = "";
for (int i = 0; i * K < len; i++) {
int start = len - (i + 1) * K;
if (start < 0) {
start = 0;
}
int end = len - i * K;
ans = S.substring(start, end) + "-" + ans;
}
return ans.substring(0, ans.length() - 1);
}
}