922. Sort Array By Parity II (Easy)

https://leetcode.com/problems/sort-array-by-parity-ii/

Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even.

Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even.

You may return any answer array that satisfies this condition.

 

Example 1:

Input: [4,2,5,7]
Output: [4,5,2,7]
Explanation: [4,7,2,5], [2,5,4,7], [2,7,4,5] would also have been accepted.

 

Note:

  1. 2 <= A.length <= 20000
  2. A.length % 2 == 0
  3. 0 <= A[i] <= 1000

 

Hints

Solutions

class Solution {
    public int[] sortArrayByParityII(int[] A) {
        int j = 1;
        for (int i = 0; i < A.length; i += 2)
            if (A[i] % 2 == 1) {
                while (A[j] % 2 == 1)
                    j += 2;

                // Swap A[i] and A[j]
                int tmp = A[i];
                A[i] = A[j];
                A[j] = tmp;
            }

        return A;
    }
}
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